传递函数计算转子动力学
%%%%%%%%%%%%%%%算例clc
clear
%等截面轴参数
d=0.03;
%A=pi*d*d/4;
%轮盘参数
D=0.2;
h=1;
%盘轴材料参数（忽略轴的质量）
%a=1;
%u=0.3;
%rou=7800;
E=2.0e11;
%G=E/(2*(1+u));
I=pi*(d^4)/64;
K1=1.5e7;
%v1=6*E*I/(a*G*A*l1*l1);
%mi=rou*pi*D^2/4*h;%轮盘的集质量
%Jp=20*D^2/8; Jd=Jp/2;
%Ji=Jp-Jd;
%参数的数组形式
L=;
M=;
K=;
v=;
J=;
k=0;
%tit=['第一阶频率的振型和弯矩图';'第二阶频率的振型和弯矩图';'第三阶频率的振型和弯矩图'];
for w=0:0.01:4000;
for i=1:5;
T(:,:,i)=[1+(L(i)^3)*(1-v(i))*(M(i)*w^2-K(i))/(6*E*I) L(i)+L(i)^2*J(i)*w^2/(2*E*I) L(i)^2/(2*E*I) L(i)^3*(1-v(i))/(6*E*I);
(L(i)^2)*(M(i)*w^2-K(i))/(2*E*I) 1+L(i)*J(i)*w^2/(E*I) L(i)/(E*I) L(i)^2/(2*E*I);
L(i)*(M(i)*w^2-K(i)) J(i)*w^2 1 L(i);
M(i)*w^2-K(i) 0 0 1];
end
H=T(:,:,1);
for i2=2:5;
H=T(:,:,i2)*H;
end
F=H(3,1)*H(4,2)-H(3,2)*H(4,1);
if F*(-1)^k < 0 %求解各阶频率
k=k+1;
wi(k)=w;
w=wi(k)
ni(k)=wi(k)*30/pi; %求解临界转速
end
end
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