求救，谢谢大家了，这个程序是怎么了MATLAB,函数加了引号还不行
A=[-17.7166,5.1179;50.3437,-20.9333;-99.3832,66.756;236.1567,-192.9286;-169.4007,141.9878];b=;
x0=;
x=fmincon('((405.5574*x(3)-334.9164*x(4)+35.0546)^2+(-17.7166*x(3)+5.1179*x(4)+36.0007)^2)^(1/2)',x0,A,b)
Warning: Large-scale (trust region) method does not currently solve this type of problem,
switching to medium-scale (line search).
> In fmincon at 260
??? Error using ==> fmincon
FMINCON cannot continue because user supplied objective function failed with the following error:
Error using ==> inlineeval
Error in inline expression ==> ((405.5574*x(3)-334.9164*x(4)+35.0546)^2+(-17.7166*x(3)+5.1179*x(4)+36.0007)^2)^(1/2)
??? Error using ==> eval
Index exceeds matrix dimensions.
谢谢，很不好意思 你的函数中只有两个变量，却用了x(3)和x(4)，因此出现“Index exceeds matrix dimensions”的警告。分别改为x(1)和x(2)后，得到了如下结果，不知是否你箱要的？
x=fmincon('((405.5574*x(1)-334.9164*x(2)+35.0546)^2+(-17.7166*x(1)+5.1179*x(2)+36.0007)^2)^(1/2)',x0,A,b)
Warning: Large-scale (trust region) method does not currently solve this type of problem,
switching to medium-scale (line search).
> In fmincon at 260
Optimization terminated: Magnitude of directional derivative in search
direction less than 2*options.TolFun and maximum constraint violation
is less than options.TolCon.
Active inequalities (to within options.TolCon = 1e-006):
lower upper ineqlin ineqnonlin
5
x =
2.5212
3.1154
感谢
x0=;这个起始点变化为什么结果不变，它对结果有什么影响？
页:
[1]