声振论坛

 找回密码
 我要加入

QQ登录

只需一步,快速开始

查看: 1354|回复: 5

[编程技巧] 怎么化简表达式啊(急等)

[复制链接]
发表于 2012-5-26 17:09 | 显示全部楼层 |阅读模式

马上注册,结交更多好友,享用更多功能,让你轻松玩转社区。

您需要 登录 才可以下载或查看,没有账号?我要加入

x
我在仿真过程中需要解方程组,但改来改去结果总是NAN+NANi(本来是个超级长的式子,我复制粘贴后回车就出现NAN+NANi),我看了看每个方程也都特别长,我想是不是该中间过程先化简下方程啊,各位大侠有什么办法吗,知道我可能错在哪了吗?

下面是我编的一部分解方程组,是不是这样弄不太好?
V0=-20*I0+EXH(1);
VL=20*IL+EXH(2);
[V0C,VLC,I0C,ILC]=ds;
EQ1=strrep('V0=V0C','V0C',V0C)
EQ2=strrep('VL=VLC','VLC',VLC)
EQ3=strrep('I0=I0C','I0C',I0C)
EQ4=strrep('IL=ILC','ILC',ILC)
EQ5=strrep('V0=V0B','V0B',char(V0))
EQ6=strrep('VL=VLB','VLB',char(VL))
[V0,VL,I0,IL,C1,C2]=solve(EQ1,EQ2,EQ3,EQ4,EQ5,EQ6);


EQ1 =

V0=sin(1/1000000*(119203220215-5641370745079159268650*i)^(1/2)*0)*C2+cos(1/1000000*(119203220215-5641370745079159268650*i)^(1/2)*0)*C1+37484314446636736100273584941584824552049940747472170404103440599656404199613136896000000000/31963066197040279143654715096957197156510546472959281644978970026190237648510940689821882313015184041*exp(-6007535325413593/36028797018963968*i*0*2^(1/2))+69543296829226364888593511222388121122421972381035384824885566854602165488412996403200000000/31963066197040279143654715096957197156510546472959281644978970026190237648510940689821882313015184041*i*exp(-6007535325413593/36028797018963968*i*0*2^(1/2))


EQ2 =

VL=sin(1/1000000*(119203220215-5641370745079159268650*i)^(1/2)*5)*C2+cos(1/1000000*(119203220215-5641370745079159268650*i)^(1/2)*5)*C1+37484314446636736100273584941584824552049940747472170404103440599656404199613136896000000000/31963066197040279143654715096957197156510546472959281644978970026190237648510940689821882313015184041*exp(-6007535325413593/36028797018963968*i*5*2^(1/2))+69543296829226364888593511222388121122421972381035384824885566854602165488412996403200000000/31963066197040279143654715096957197156510546472959281644978970026190237648510940689821882313015184041*i*exp(-6007535325413593/36028797018963968*i*5*2^(1/2))


EQ3 =

I0=100/79753*i*cos(1/1000000*(119203220215-5641370745079159268650*i)^(1/2)*0)*(119203220215-5641370745079159268650*i)^(1/2)*C2-100/79753*i*sin(1/1000000*(119203220215-5641370745079159268650*i)^(1/2)*0)*(119203220215-5641370745079159268650*i)^(1/2)*C1+14539679002158187855062333741478388479390406414745717843574189952499291307282075406494140625000/31963066197040279143654715096957197156510546472959281644978970026190237648510940689821882313015184041*i*2^(1/2)*exp(-6007535325413593/36028797018963968*i*0*2^(1/2))+7836986805621391373144896270950255829492401049407201476539700367644411852387833789062500000000/31963066197040279143654715096957197156510546472959281644978970026190237648510940689821882313015184041*2^(1/2)*exp(-6007535325413593/36028797018963968*i*0*2^(1/2))


EQ4 =

IL=100/79753*i*cos(1/1000000*(119203220215-5641370745079159268650*i)^(1/2)*5)*(119203220215-5641370745079159268650*i)^(1/2)*C2-100/79753*i*sin(1/1000000*(119203220215-5641370745079159268650*i)^(1/2)*5)*(119203220215-5641370745079159268650*i)^(1/2)*C1+14539679002158187855062333741478388479390406414745717843574189952499291307282075406494140625000/31963066197040279143654715096957197156510546472959281644978970026190237648510940689821882313015184041*i*2^(1/2)*exp(-6007535325413593/36028797018963968*i*5*2^(1/2))+7836986805621391373144896270950255829492401049407201476539700367644411852387833789062500000000/31963066197040279143654715096957197156510546472959281644978970026190237648510940689821882313015184041*2^(1/2)*exp(-6007535325413593/36028797018963968*i*5*2^(1/2))


EQ5 =

V0=-20*I0+841724055033465/27055533852947748863454245552128*i*(-1)^(6007535325413593/22517998136852480/pi)+4869032366694846250327380859215/487389168713781286809295773452177656065348861952*(-1)^(-6007535325413593/45035996273704960*2^(1/2)/pi)+921532590084783129383827089555/30461823044611330425580985840761103504084303872*i*(-1)^(-6007535325413593/45035996273704960*2^(1/2)/pi)-4869032366694846250327380859215/487389168713781286809295773452177656065348861952-1869229625234157089886635501715/30461823044611330425580985840761103504084303872*i


EQ6 =

VL=20*IL+2570993305636493/216444270823581990907633964417024*i*(-1)^(6007535325413593/22517998136852480/pi)+6223660823902523/216444270823581990907633964417024*(-1)^(6007535325413593/22517998136852480/pi)+123892324875181571175840588188779/3899113349710250294474366187617421248522790895616*(-1)^(-6007535325413593/45035996273704960*2^(1/2)/pi)+9034861109353615519822123666003/3899113349710250294474366187617421248522790895616*i*(-1)^(-6007535325413593/45035996273704960*2^(1/2)/pi)-236007831144812598006926628834411/3899113349710250294474366187617421248522790895616-55349759082299813952434960108115/3899113349710250294474366187617421248522790895616*i







回复
分享到:

使用道具 举报

发表于 2012-5-27 01:04 | 显示全部楼层
符号解? 好奇问下, 有需要一定得用符号解吗?
 楼主| 发表于 2012-5-30 10:55 | 显示全部楼层
回复 2 # ChaChing 的帖子

我初学不太懂,有错就改有错就改,就改成这样了
 楼主| 发表于 2012-5-30 10:56 | 显示全部楼层
回复 2 # ChaChing 的帖子

我是初学,不太懂也,只是报错就改最后成这个样子了
发表于 2012-5-30 14:38 | 显示全部楼层
回复 1 # jr7121062jr 的帖子

感觉方程本身你没有搞清楚,不可能有这么复杂的数值,相差那么多数量级的数字有意义么……
头像被屏蔽
发表于 2012-5-30 16:22 | 显示全部楼层
提示: 作者被禁止或删除 内容自动屏蔽
您需要登录后才可以回帖 登录 | 我要加入

本版积分规则

QQ|小黑屋|Archiver|手机版|联系我们|声振论坛

GMT+8, 2024-6-2 02:09 , Processed in 0.058611 second(s), 22 queries , Gzip On.

Powered by Discuz! X3.4

Copyright © 2001-2021, Tencent Cloud.

快速回复 返回顶部 返回列表