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适合初学的人研究之用,非常经典!
问题一:悬臂梁受重力作用发生大变形,求其固有频率。
基本过程:
1、建模
2、静力分析
NLGEOM,ON
STRES,ON
3、求静力解
4、开始新的求解:modal
STRES,ON
UPCOORD,1,ON 修正坐标
SOLVE...
5、扩展模态解
6、察看结果
- /PREP7
- ET,1,BEAM189 !使用beam189梁单元
- MPTEMP,,,,,,,,
- MPTEMP,1,0
- MPDATA,EX,1,,210e9
- MPDATA,PRXY,1,,0.3
- MPDATA,DENS,1,,7850
- SECTYPE, 1, BEAM, RECT, secA, 0 !定义梁截面secA
- SECOFFSET, CENT
- SECDATA,0.005,0.01,0,0,0,0,0,0,0,0
- K, ,,,, !建模与分网
- K, ,2,,,
- K, ,2,1,,
- LSTR, 1, 2
- LATT,1, ,1, , 3, ,1
- LESIZE,1, , ,20, , , , ,1
- LMESH, 1
- FINISH
-
- /SOL !静力大变形求解
- ANTYPE,0
- NLGEOM,1
- PSTRES,ON !计及预应力效果
- DK,1, , , ,0,ALL, , , , , ,
- ACEL,0,9.8,0, !只考虑重力作用
- TIME,1
- AUTOTS,1
- NSUBST,20, , ,1
- KBC,0
- SOLVE
- FINISH
-
- /SOLUTION
- ANTYPE,2 !进行模态求解
- MSAVE,0
- MODOPT,LANB,10
- MXPAND,10, , ,0 !取前十阶模态
- PSTRES,1 !打开预应力效应
- MODOPT,LANB,10,0,0, ,OFF
- UPCOORD,1,ON !修正坐标以得到正确的应力
- PSOLVE,TRIANG !三角化矩阵
- PSOLVE,EIGLANB !提取特征值和特征向量
- FINISH
- /SOLU
- EXPASS,1 !扩展模态解
- PSOLVE,EIGEXP
- FINISH
-
- /POST1
- SET,LIST !观察结果
- FINISH
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问题二:循环对称结构模态分析
这是ANSYS HELP里的例子,但那个命令流似乎有些问题,下面是整理过的命令流。
基本过程:
1、建模
2、define cyclic
3、定义约束
4、求模态解
5、展开并察看结果
- r1=5 !建模
- r2=10
- d1=2
- nsect=24
- alpha_deg=360/nsect
- alpha_rad=2*acos(-1)/nsect
-
- /prep7
- csys,1
- k,1,0,0,0
- k,2,0,0,d1
- k,3,r1,0,0
- k,4,r1,0,d1
- l,3,4
- arotat,1,,,,,,1,2,alpha_deg/2
- k,7,r2,0,0
- k,8,r2,0,d1
- l,7,8
- arotat,5,,,,,,1,2,alpha_deg/2
- arotat,2,,,,,,1,2,alpha_deg/2
- arotat,6,,,,,,1,2,alpha_deg/2
- a,5,6,10,9
- mshkey,1
- et,1,181
- r,1,0.20
- r,2,0.1
- mp,ex,1,10e6
- mp,prxy,1,0.3
- mp,dens,1,1e-4
- esize,0.5
- asel,,,,1,4
- aatt,,1
- asel,,,,5
- aatt,,2
- allsel
-
- CYCLIC, , , ,'CYCLIC' !定义基本扇区
- AMESH,all !分网
- FINISH
-
- /SOL !求模态解
- ANTYPE,2
- MODOPT,LANB,10
- MXPAND,10, , ,0
- PSTRES,0
- MODOPT,LANB,10,0,0, ,OFF
- DK,5, , , ,0,UZ, , , , , ,
- SOLVE
- FINISH
-
- /POST1
- SET,LIST
- SET, , ,1, , , ,4,
- /CYCEXPAND, ,ON
- PLNS,U,SUM !观察扩展模态
- FINISH
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问题三:三角平台受谐波载荷作用,求结构响应
谐波载荷为作用在平台上面一点的集中力,幅值为10N,频率范围5Hz~70Hz
基本过程:
1、建模
2. 求模态解
3、用模态叠加法作谐分析
4. 观察结果
- /PREP7 !建模
- ET,1,BEAM189
- ET,2,SHELL93
- R,1,0.01, , , , , ,
- MP,EX,1,210e9
- MP,PRXY,1,0.3
- MP,DENS,1,7850
- SECTYPE, 1, BEAM, RECT, secA, 0
- SECOFFSET, CENT
- SECDATA,0.005,0.008,0,0,0,0,0,0,0,0
- K, ,-0.5,,,
- K, ,0.5,,,
- K, ,,,1,
- K, ,,1,1,
- K, ,-0.5,1,,
- K, ,0.5,1,,
- K, ,,,0.5,
- A,4,5,6
- LSTR, 1, 5
- LSTR, 3, 4
- LSTR, 2, 6
- LSEL,S,LINE,,4,6
- LATT,1,1,1, , 7, ,1
- LSEL, , , ,ALL
- LESIZE,ALL, , ,10, , , , ,1
- LMESH,4,6
- TYPE, 2
- MSHAPE,0,2D
- MSHKEY,1
- AMESH,1
- FINISH
-
- /SOL !为了使用模态叠加法谐分析
- ANTYPE,2
- MODOPT,LANB,20 !先取结构前20阶模态
- MXPAND,20, , ,0
- MODOPT,LANB,20,0,0, ,OFF
- KSEL,S,KP,,1,3
- DK,ALL, , , ,0,ALL, , , , , ,
- SOLVE
- FINISH
-
- !/POST1 !最好事先看一下模态结果
- !SET,LIST !以了解模态频率范围
- !FINISH
-
- /SOL !模态叠加法谐响应分析
- ANTYPE,3
- HROPT,MSUP
- HROUT,ON
- HROPT,MSUP,20, ,
- HROUT,ON,OFF,0
- F,177,FY,-10, !施加10N的力在节点177的负Y方向
- HARFRQ,5,70, !载荷的强制频率范围
- NSUBST,200,
- KBC,1
- ALPHAD,5,
- SOLVE
- FINISH
-
- /POST26 !察看位移响应
- FILE,,rfrq
- NUMVAR,20
- NSOL,2,139,U,Y,
- PLVAR,2
- FINISH
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问题四:三角平台受一地震谱激励,求应力分布和支反力
基本过程:
1、建模
2、求模态解
3、求谱解
4、扩展模态
5、模态合并
6、观察结果
- /PREP7 !建模
- ET,1,BEAM189
- ET,2,SHELL93
- R,1,0.01, , , , , ,
- MP,EX,1,210e9
- MP,PRXY,1,0.3
- MP,DENS,1,7850
- SECTYPE, 1, BEAM, RECT, secA, 0
- SECOFFSET, CENT
- SECDATA,0.005,0.008,0,0,0,0,0,0,0,0
-
- K, ,-0.5,,,
- K, ,0.5,,,
- K, ,,,1,
- K, ,,1,1,
- K, ,-0.5,1,,
- K, ,0.5,1,,
- K, ,,,0.5,
- A,4,5,6
- LSTR, 1, 5
- LSTR, 3, 4
- LSTR, 2, 6
- LSEL,S,LINE,,4,6
- LATT,1,1,1, , 7, ,1
- LSEL, , , ,ALL
- LESIZE,ALL, , ,10, , , , ,1
- LMESH,4,6
- TYPE, 2
- MSHAPE,0,2D
- MSHKEY,1
- AMESH,1
- FINISH
-
- /SOL !取前十阶模态
- ANTYPE,2
- MODOPT,LANB,10
- KSEL,S,KP,,1,3
- DK,ALL, , , ,0,ALL, , , , , ,
- SOLVE
- FINISH
-
- /SOL !谱分析
- ANTYPE,8
- SPOPT,SPRS,10,1
- SVTYP,3
- SED,0,1,0, !给出激励方向
- FREQ,0.25,1.34,6.73,14.6,28.9,0,0,0,0 !激励谱
- SV,0,0.00073,0.00016,0.00034,0.00034,0.00052,
- SOLVE
- FINISH
-
- /SOL !扩展模态
- ANTYPE,2
- EXPASS,1
- MXPAND,10,0,0,1,0.001,
- SOLVE
- FINISH
-
- /SOL !模态合并
- ANTYPE,8
- SRSS,0.001,DISP
- SOLVE
-
- /POST1 !观察结果
- SET,LIST
- /INPUT,,mcom
- PRRSOL,F
- FINISH
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问题五:三角平台受时程载荷作用,求应力分布和变形过程
基本过程:
1、建模
2. 施加随时间变化载荷,定义载荷步
3、求解
4. 在POST1和POST26中观察结果
- /PREP7 !建模
- ET,1,BEAM189
- ET,2,SHELL93
- R,1,0.01, , , , , ,
- MP,EX,1,210e9
- MP,PRXY,1,0.3
- MP,DENS,1,7850
- SECTYPE, 1, BEAM, RECT, secA, 0
- SECOFFSET, CENT
- SECDATA,0.005,0.008,0,0,0,0,0,0,0,0
- K, ,-0.5,,,
- K, ,0.5,,,
- K, ,,,1,
- K, ,,1,1,
- K, ,-0.5,1,,
- K, ,0.5,1,,
- K, ,,,0.5,
- A,4,5,6
- LSTR, 1, 5
- LSTR, 3, 4
- LSTR, 2, 6
- LSEL,S,LINE,,4,6
- LATT,1,1,1, , 7, ,1
- LSEL, , , ,ALL
- LESIZE,ALL, , ,10, , , , ,1
- LMESH,4,6
- TYPE, 2
- MSHAPE,0,2D
- MSHKEY,1
- AMESH,1
- FINISH
-
- /SOL
- ANTYPE,4
- TRNOPT,FULL !完全法瞬态分析
- KSEL,S,KP,,1,3
- DK,ALL, , , ,0,ALL, , , , , ,
- OUTRES,ALL,1
- ALPHAD,5, !α阻尼
-
- TIME,2 !定义载荷曲线
- AUTOTS,1
- NSUBST,50, , ,1
- KBC,0
- SFA,ALL,1,PRES,500
- LSWRITE,1,
-
- TIME,3
- LSWRITE,2,
-
- TIME,4
- SFA,ALL,1,PRES,150
- KBC,1
- LSWRITE,3,
-
- TIME,5
- SFA,ALL,1,PRES,
- LSWRITE,4,
-
- LSSOLVE,1,4,1, !求解
- FINISH
-
- /POST26 !观察变形随时间的变化
- NSOL,2,177,U,Y,uyy
- PLVAR,2
- FINISH
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[ 本帖最后由 yejet 于 2006-9-1 09:05 编辑 ] |