可以采用初应变法
给个例子
fini
/clear
/prep7
/title,the analysis of ganggou bridge
et,1,solid95
et,2,link8
mp,dens,1,2600
mp,ex,1,3.5e10
mp,prxy,1,0.1667
mp,dens,2,7800
mp,ex,2,1.95e11
mp,prxy,2,0.3
!直径15.24mm,标准强度1860MPa,单根张拉控制吨位195.5kN
areagjx=1.4e-4
*dim,gjarea,array,4
gjarea(1)=15*areagjx
gjarea(2)=18*areagjx
gjarea(3)=20*areagjx
gjarea(4)=22*areagjx
F=195.5e3 !每根钢绞线张拉控制吨位195.5kN
E=1.95e11 !钢绞线弹模
L=1 !每根钢绞线长1m
detL=F*L/(E*areagjx) !每根钢绞线单元的伸长量
istrn=detL/(detL+L) !每根钢绞线单元的的拉应变
r,2,gjarea(1),istrn !定义各种钢束的实常数
r,3,gjarea(2),istrn
r,4,gjarea(3),istrn
r,5,gjarea(4),istrn
acel,,9.8
也可以采用加温度的方法
fini
/clear
fini
/title,“预应力简支梁分析”
/prep7
gjx_ex=2e11
gjx_a=60e-4
hnt_ex=3.5e10
yyl=200000
xzxs=1.2e-5
et,1,link8
et,2,solid95
r,1,gjx_a
mp,ex,1,gjx_ex
mp,dens,1,7800
mp,prxy,1,0.3
mp,alpx,1,xzxs
mp,ex,2,hnt_ex
mp,dens,2,2500
mp,prxy,2,0.1667
blc4,,,1,2,30
wpave,,0.4
wpro,,90
vsbw,all
wpro,,-90
wpro,,,-90
wpave,0.3
vsbw,all
wpave,0.7
vsbw,all
esize,0.3
lsel,s,loc,y,0.4
lsel,r,loc,x,0.3
cm,gjx,line
lsel,s,loc,y,0.4
lsel,r,loc,x,0.7
cmsel,a,gjx
cm,gjx,line
latt,1,1,1
lmesh,all
allsel
vatt,2,,2
mshape,0,3d
mshkey,1
vmesh,all
fini
/solu
lsel,s,loc,y,0
lsel,r,loc,z,0
dl,all,,all
lsel,s,loc,y,0
lsel,r,loc,z,30
dl,all,,ux
dl,all,,uy
cmsel,s,gjx
bfl,all,temp,-yyl/(xzxs*gjx_ex*gjx_a)
allsel
acel,,9.8
solve
fini |