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发表于 2008-1-3 11:19
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请问这个错误讯息是什么意思呢??
P R O B L E M S I Z E
NUMBER OF ELEMENTS IS 10
NUMBER OF NODES IS 128
NUMBER OF NODES DEFINED BY THE USER 128
TOTAL NUMBER OF VARIABLES IN THE MODEL 384
(DEGREES OF FREEDOM PLUS ANY LAGRANGE MULTIPLIER VARIABLES)
END OF USER INPUT PROCESSING
JOB TIME SUMMARY
USER TIME (SEC) = 0.10000
SYSTEM TIME (SEC) = 0.0000
TOTAL CPU TIME (SEC) = 0.10000
WALLCLOCK TIME (SEC) = 1
1
Abaqus Version 6.7-1 DATE 03-Jan-2008 TIME 11:12:48
For use by Team oDDiTy under license from ABAQUS, Inc.
THREE LAYER COMPOSITE PLATE - SOLID ELEMENTS (CRD20R) STEP 1 INCREMENT 1
TIME COMPLETED IN THIS STEP 0.00
S T E P 1 S T A T I C A N A L Y S I S
AUTOMATIC TIME CONTROL WITH -
A SUGGESTED INITIAL TIME INCREMENT OF 1.00
AND A TOTAL TIME PERIOD OF 1.00
THE MINIMUM TIME INCREMENT ALLOWED IS 1.000E-05
THE MAXIMUM TIME INCREMENT ALLOWED IS 1.00
LINEAR EQUATION SOLVER TYPE DIRECT SPARSE
STEP 1, INCREMENT 1, TIME INCREMENT= 0.100E+01, TOTAL TIME= 0.100E+01
REORDERING OF EQUATIONS TO MINIMIZE WAVEFRONT HAS CHANGED THE MEMORY AND DISK ESTIMATES TO:
M E M O R Y A N D D I S K E S T I M A T E
SUMMARY FOR CURRENT NODE ORDERING
(NOTE THAT IF NODE ORDERING CHANGES THE SIZE ESTIMATES FOR THE STEPS WILL CHANGE)
STEP MAXIMUM DOF FLOATING PT MINIMUM MEMORY MEMORY TO REQUIRED DISKSPACE
WAVEFRONT OPERATIONS REQUIRED MINIMIZE I/O
PER ITERATION (MBYTES) (MBYTES) (KBYTES)
1 72 8.62E+005 3.78 4.57 287.72
---- --------- ------------ ------------- ------------- -------------
MAX 72 8.62E+005 3.78 4.57 287.72
THE TABLE ABOVE PROVIDES A STEP BY STEP SUMMARY OF SOME BASIC SIZING INFORMATION
FOR THE PROBLEM. SOME FURTHER DESCRIPTION OF THE PARAMETERS GIVEN FOLLOWS:
(1) MAXIMUM DOF WAVEFRONT - SIZE OF THE BIGGEST FRONT IN THE EQUATION SOLVER.
PROVIDES A BASIC SIZING OF THE MOST MEMORY INTENSIVE SEGMENT OF SOLVER.
(2) FLOATING POINT OPERATIONS PER ITERATION - MEASURE OF THE NUMBER OF FLOATING
POINT OPERATIONS REQUIRED FOR A SINGLE SOLVER PASS. ON A GIVEN PLATFORM
THE TIME REQUIRED FOR A SOLVER PASS WILL BE ROUGHLY A LINEAR FUNCTION
OF THIS VALUE.
NOTE - EXCEPT FOR THE FIRST STEP, THE VALUE IN THIS TABLE DOES NOT INCLUDE
ADDITIONAL FLOATING POINT OPERATIONS THAT ARE REQUIRED IN MULTIPLE LOAD
CASE STEPS WHEN CONSTRAINTS CHANGE FROM LOAD CASE TO LOAD CASE. THIS
SITUATION CAUSES A REORDERING TO BE PERFORMED, AT WHICH TIME AN UPPER
BOUND ON THE NUMBER OF ADDITIONAL FLOATING POINT OPERATIONS WILL BE
CALCULATED AND INCLUDED UNDER THE ESTIMATE SUMMARIES FOR THE RELEVANT
STEPS (SEE NOTE BELOW ON REORDERING).
(3) MINIMUM MEMORY REQUIRED - MINIMUM POSSIBLE MEMORY VALUE FOR standard_memory
THAT ENABLES Abaqus TO SOLVE THE PROBLEM. USE OF MEMORY WILL BE MINIMIZED BY
WRITING AS MUCH INFORMATION AS POSSIBLE TO DISK WHICH WILL INCREASE I/O TIME.
(4) MEMORY TO MINIMIZE I/O - VALUE OF standard_memory THAT ALLOWS Abaqus TO KEEP
ALL SIGNIFICANT SCRATCH FILES IN MEMORY. THIS WILL MINIMIZE I/O TIME FOR THE USER
WITH ACCESS TO A LARGE AMOUNT OF MEMORY.
(5) REQUIRED DISKSPACE - AMOUNT OF DISK REQUIRED FOR SCRATCH FILES. THESE WILL BE
DELETED AT THE END OF THE ANALYSIS.
NOTE - WHENEVER POSSIBLE THE USER SHOULD SET standard_memory TO BE LESS THAN THE
PHYSICAL MEMORY ON THE MACHINE. UNLESS NECESSARY USERS SHOULD NOT MAKE USE
OF VIRTUAL MEMORY EVEN IN AN ATTEMPT TO KEEP SCRATCH FILES IN MEMORY.
NOTE - IF A REORDERING IS PERFORMED (THIS WILL ONLY GENERALLY BE DONE FOR FINITE-
SLIDING CONTACT PROBLEMS), THE SIZE ESTIMATES DONE AT THIS TIME WILL NO LONGER
BE VALID. THE ESTIMATES WILL BE REDONE IN THE EVENT OF A REORDERING AND A NEW
SUMMARY WILL BE PRINTED FOR THE REMAINING STEPS.
S I Z E E S T I M A T E S F O R C U R R E N T S T E P
NUMBER OF EQUATIONS 384
MAX DOF WAVEFRONT 72
FLOATING POINT OPS PER SOLVER ITERATION 8.62E+005
MEMORY USED FOR STEP 256.00 MBYTES
ESTIMATED FILE SIZES
FILE KWORDS KBYTES
.fct 17.328 135.375
.nck 0.600 4.688
.opr 18.900 147.656
------- ------- -------
TOTAL 36.828 287.719
THE ANALYSIS IS ENDED BECAUSE OF THE PROBLEMS ENCOUNTERED
LOOK AT THE MSG FILE FOR THE CAUSE OF THE TERMINATION
ANALYSIS COMPLETE
WITH 1 ERROR MESSAGES ON THE MSG FILE |
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