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[结构分析] 在BEAM 23 裡,怎樣去設置 I BEAM 的REAL CONSTANT?

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发表于 2009-2-6 05:22 | 显示全部楼层 |阅读模式

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大家好,我想問一個簡單的問題

在BEAM 23 裡,怎樣去設置 I BEAM 的REAL CONSTANT?
它有一個 -50 , -30, 0, 30, 50 的輸入介面叫我輸入一組面積
我看了ANSYS 的英文教學也不清楚它在說甚麼
請教教我,這是我第3年的大學報告

-------    <126mm
    |        < 6.6mm     全高:353.4mm
-------    <126mm



The general cross-section option (KEYOPT(6)=4) allows inputting a sectionheight and a five-location area distribution.  If the section is symmetric, only thefirst three of the five areas need be input since the fourth area defaults to thesecond and the fifth area defaults to the first.  The areas input should be aweighted distribution at the -50% integration point A(-50), the -30% integrationpoint A(-30), the 0% integration point A(0), the 30% integration point A(30), andthe 50% integration point A(50).  Each area A(i) is as shown in Figure 4.23-2. The height is defined as the distance between the

                               
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50% integration points,and is not necessarily the distance between the outermost fibers of the section. Determination of the input areas is accomplished as follows.  Estimate one ofthe input areas by the formula A(i) = L(i) x HEIGHT, where L(i) is the width ofthe section at integration point i (see Figure 4.23-2b).  Substitute this area alongwith the section moment of inertia, Izz, and total area, A, into the aboveequations and solve them simultaneously for the remaining two input areas. A(0) is usually the easiest to estimate; for instance, as a first guess A(0) for anI-beam would be the web thickness times the height.  A trial and errorprocedure (by modifying the estimated input area) may be needed if thecalculated input areas are inconsistent, such as a negative area.  The inputareas, A(i), are related to the true areas, At(i), corresponding to each integrationpoint, by:  
At (-50) = 0.0625 A(-50),     At (50) = 0.0625 A(50),
At (-30) = 0.28935 A(-30),    At (30) = 0.28935 A(30),
At (0)   = 0.29630 A(0)
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发表于 2009-2-11 00:19 | 显示全部楼层
这些参数一般是查型钢表得到的
网上有这样的软件
或者你去图书馆找手册查查
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