“移动温度载荷计算方法”仅供参考

guxudi

:lol
/com, units: SI, m - degree C - W - kg -sec - J
!
! Bi=h*dx/K = 60*0.002/51.9 = 0.0023 < 1
! F0 = ( Kdt ) / (rho*C*dx^2)
! assume F0= beta = 0.4
! dt = (beta*rho*C*dx^2)/K = 0.1179 (sec)
!
/title,transient analysis 2 (moving heat flux)
/filnam,transient-2
!
/triad,rbot
!
/prep7
!
wpstyle,,,,,,,,1
wpstyle,0.01,0.01,0,0.1,0.003,0,1,,5
!
blc4,0,0.1,0.1,-0.1 !0.1*0.1 m
cyl4,0.03,0.05,0.01
asba, 1, 2 !drill a hole
!
blc4,0.1,0.1,-0.01,-0.1
!
flst,2,2,5,orde,2
fitem,2,1
fitem,2,3
aovlap,p51x
!
wpstyle,,,,,,,,0
aplot
!
et,1,plane55
!*
keyopt,1,1,0
keyopt,1,3,0 !2d plane problem
keyopt,1,4,0
keyopt,1,8,0
keyopt,1,9,0
!
!aisi 1045 steel
!
uimp,1,dens, , ,7870 , !kg/m3
uimp,1,kxx, , , 51.9 , !w/m-c
uimp,1,c, , , 486, !w-s / kg-c
!
type,1
mat,1
!
esize,0.002, !element size = 0.002 m
!
mshkey,1
amesh,1
!
mshkey,0
amesh,2
!
!boundary conditions
!
/psf,hflu, ,2,0
!
!convection
!
flst,2,1,4,orde,1
fitem,2,4
sfl,p51x,conv,50, ,25,
!
finish
!
/solu
!
antype,trans
trnopt,full
nropt,auto, ,
eqslv,
!
solcontrol,on
autots,on
!
kbc,1 !step
outres,all,all,
!
!load step 1, initial conditions 25 c
!
time,0.001
deltim,0.001,0.001,0.001
timint,off !time integration = off
tunif,25,
solve
!
!load step 2..... , apply moving heat flux
!
timint,on !time integration = on
!
j=1
!
*do,i,200,80,-5
!
time,j
deltim,0.11,0.11,0.11,
!
sfedele,i+5,2,hflux !delete heat flux of previous step
!
sfe,i,2,hflux, ,5/0.002/0.002, , , !apply heat flux, face 2 , 5 w
!
eplot
!
solve
j=j+1
*enddo
!
finish
!
/post1
/eface,1
set,last
!
plnsol,temp, ,0,
finish

16443

验证，能运行