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求解圆形空心桥墩与水耦合作用时候桥墩的自振频率
fini
/clear
/prep7
cylind,5,6,0,60
cylind,6,10,0,60
cylind,10,20,0,60
et,1,solid45
mp,ex,1,3.45e10
mp,nuxy,1,0.2
mp,dens,1,2500!2.5e-6
et,2,fluid30
et,3,fluid130
r,3,20
et,4,fluid30
keyopt,4,2,1
mp,dens,2,1030
mp,sonc,2,1460
mp,dens,3,1030
mp,sonc,3,1460
mp,dens,4,1030
mp,sonc,4,1460
!!!对桥墩的网格化
type,1
real,1
mat,1
MSHKEY,0
MSHAPE,1,3D !
csys,1
vsel,s,volu,,1
vmesh,all
!!!!!!!!!!!
!!!对桥墩外围与桥墩相接触的水进行网格化
type,2
real,2
mat,2
MSHKEY,0
MSHAPE,1,3D !
csys,1
vsel,s,volu,,2
vmesh,all
!对桥墩外围与桥墩不接触的水进行网格化
type,4
real,4
mat,4
MSHKEY,0
MSHAPE,1,3D !
csys,1
vsel,s,volu,,3
vmesh,all
! 指定无限吸收边界
csys,1
nsel,s,loc,x,20
type,3
real,3
mat,3
esurf
! 标识流固交接面
nsel,s,loc,x,6
esel,s,type,,2
sf,all,fsi,1
allsel,all
/solu
nsel,s,loc,x,5,6
nsel,r,loc,z,0
d,all,all
antype,modal
modopt,damp,10
mxpand,10,,,yes
allsel,all
solve
finish
/post1
set,list
运行的时候出现错误:
Node no. 2620 of the Fluid130 Acoustic Absorbing element 13065 should lie on a SPhere of radius 20;instead lies at a radius of 54.156 .Ensure that the radius input through the element real constant matches with that of the absorbing boundary.
大家看看问题出在什么地方。
下面是这个圆形空心墩在空气中的自振频率计算的代码,计算的结果和在水中计算的结果完全一样,大家看看是怎么回事啊?fini
/clear
/prep7
cylind,5,6,0,60
et,1,solid45
mp,ex,1,3.45e10
mp,nuxy,1,0.2
mp,dens,1,2500!2.5e-6
SMRTSIZE,2
vmesh,all
fini
/solu
antype,modal
modopt,lanb,20
nsel,s,loc,z,0
d,all,all
mxpand,20
allsel,all
solve
finish
/post1
set,list
桥墩在水中和在空气中计算出来的频率都是一样的,如下:
***** INDEX OF DATA SETS ON RESULTS FILE *****
SET TIME/FREQ LOAD STEP SUBSTEP CUMULATIVE
1 2.1532 1 1 1
2 2.1558 1 2 2
3 10.069 1 3 3
4 10.806 1 4 4
5 10.813 1 5 5
6 15.497 1 6 6
7 24.587 1 7 7
8 24.617 1 8 8
9 26.141 1 9 9
10 26.433 1 10 10
11 27.790 1 11 11
12 28.065 1 12 12
13 30.237 1 13 13
14 31.776 1 14 14
15 31.873 1 15 15
16 38.720 1 16 16
17 38.792 1 17 17
18 39.230 1 18 18
19 39.295 1 19 19
20 46.345 1 20 20
各位大侠能否看看是怎么回事呢?
[ 本帖最后由 ywl_5234 于 2009-4-21 07:51 编辑 ] |
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