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现在我想在三个压电陶瓷中加载两个100sinwt和100coswt的交变电压。(相位相差90度)
压电陶瓷是沿z向极化的。其中第一和第三压电陶瓷极化方向相反,加载100coswt。第二个极化方向与第一个压电陶瓷相同,但要加载100sinwt。
因为刚刚接触压电分析。所以又很多问题不太懂。麻烦大家指点
1、极化方向方面:
压电陶瓷我选用pzt-8,参数按照书上查得。陶瓷伸长方向沿总体笛卡尔坐标系的z轴。这样的话我的电压是不是应该加在两个侧面?
2、压电陶瓷变形引起底板变形。所以我体之间用了vglue对吗?
3、就是电压的加载形式。我直接选择面。这样对吗?
4、就是我现在最不知道的。。
相位相差90度的电压应该怎么加载呢?
附上和压电陶瓷有关的命令流(自己编的不太规范,大家别见笑)
以及模型
命令流:
et,2,solid5,3
!~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
MP,DENS,3,7500 !+
MP,PERX,3,7.124e-09
MP,PERY,3,7.124e-09
MP,PERZ,3,5.841e-09
TB,ANEL,3
tbdata,1,1.32e11,7.1e10,7.3e10,0,0,0
tbdata,7,1.32e11,7.3e10,0,0,0
tbdata,12,11.5E10,0,0,0
tbdata,16,3.06E10,0,0
tbdata,19,2.56E10,0
tbdata,21,2.56E10
TB,PIEZ,3
tbdata,3,-4.1
tbdata,6,-4.1
tbdata,9,14.1
tbdata,14,10.5
tbdata,16,10.5
!~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
MP,DENS,4,7500 !-
MP,PERX,4,7.124e-09
MP,PERY,4,7.124e-09
MP,PERZ,4,5.841e-09
TB,ANEL,4
tbdata,1,1.32e11,7.1e10,7.3e10,0,0,0
tbdata,7,1.32e11,7.3e10,0,0,0
tbdata,12,11.5E10,0,0,0
tbdata,16,3.06E10,0,0
tbdata,19,2.56E10,0
tbdata,21,2.56E10
TB,PIEZ,4
tbdata,3,4.1
tbdata,6,4.1
tbdata,9,-14.1
tbdata,14,-10.5
tbdata,16,-10.5
!~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
BLOCK,0,h1,-b1,b1,-l1,l1,
BLOCK,-h2,0,-b2,b2,-l2,l2,
VGEN,2,2, , , , ,32e-3, ,1
VGEN,2,2, , , , ,-32e-3, ,1
vsel,all
vglue,all
NUMCMP,all
TYPE, 2
MAT, 2
REAL,
ESYS, 0
SECNUM,
ESIZE,0.003,0,
MSHAPE,0,3D
MSHKEY,1
VSEL, , , ,1,2
VMESH,all
TYPE, 2
MAT, 3
REAL,
ESYS, 0
SECNUM,
ESIZE,0.004,0,
MSHAPE,0,3D
MSHKEY,1
VSEL, , , , 3
VMESH,all
TYPE, 1
MAT, 1
REAL,
ESYS, 0
SECNUM,
ESIZE,0.015,0,
SMRT,8
MSHAPE,1,3D
MSHKEY,0
VSEL, , , , 4
VMESH,all
!~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
ASEL,S,,,18
NSLA,S,1
cp,18,volt,all
allsel,all
ASEL,S,,,19
NSLA,S,1
cp,19,volt,all
allsel,all
ASEL,S,,,6
NSLA,S,1
cp,6,volt,all
allsel,all
ASEL,S,,,7
NSLA,S,1
cp,7,volt,all
allsel,all
ASEL,S,,,12
NSLA,S,1
cp,12,volt,all
allsel,all
ASEL,S,,,13
NSLA,S,1
cp,13,volt,all
allsel,all
da,18,volt,VOL
da,19,volt,VOL
da,6,volt,VOL
da,7,volt,VOL
da,12,volt,VOL
da,13,volt,VOL
fini
save
!~~~~~~~~~~~~~~~~~~~~~~~~模态分析
/SOL
ANTYPE,2
MSAVE,0
MODOPT,LANB,20
EQSLV,SPAR
MXPAND,20, , ,0
LUMPM,0
PSTRES,0
MODOPT,LANB,20,0,0, ,OFF
SOLVE
FINISH |