声振论坛

 找回密码
 我要加入

QQ登录

只需一步,快速开始

查看: 8737|回复: 39

(转帖,英文的)一篇论述加速度,速度,位移转换的文章

  [复制链接]
发表于 2010-12-22 09:09 | 显示全部楼层 |阅读模式

马上注册,结交更多好友,享用更多功能,让你轻松玩转社区。

您需要 登录 才可以下载或查看,没有账号?我要加入

x
本帖最后由 tenglang 于 2010-12-22 09:58 编辑

主要论述的是加速度转换到速度和位移
原帖地址: http://blog.prosig.com/2010/12/16/methods-of-conversion-between-acceleration-velocity-and-displacement/#more-1569

评分

1

查看全部评分

回复
分享到:

使用道具 举报

 楼主| 发表于 2010-12-22 09:31 | 显示全部楼层

(转帖,英文的)一篇论述加速度,速度,位移转换的文章

本帖最后由 tenglang 于 2010-12-22 09:57 编辑

不小心粘到第二帖来了,sorry

             calculus.jpg From time to time I meet engineers who are interested in the conversions between acceleration, velocity and displacement. Often, they have measured acceleration, but are interested in displacement or vice versa. Equally, velocity is often used to find acceleration.
This article will attempt to outline the nature of the conversation between these units and will suggest the preferred method for doing so. We will deliberately avoid some of the more complex mathematics. For the mathematically minded there are already other excellent articles on this blog that describe the mathematics involved. This article will also suggest the best method for such a conversion.
Before discussing these conversions we should consider what these measurements are.
1. Displacement is the measurement of a distance travelled. If an object has moved 10 meters then is has been displaced by 10 meters or 10 m.
2. Velocity, often incorrectly called speed, is the measurement of a certain displacement in a certain time. For example an object that moves 10 meters in a second is travelling at the velocity of 10 meters per second or 10 m/s.
3.Velocity can be both negative and positive as it is a vector. The magnitude of a velocity is the speed, this can only be positive.
4. Acceleration is the rate of change of velocity. If we had a stationary object, it would have no acceleration. The rate of change of its velocity is zero. And, it follows, that an object travelling with a constant velocity of 10 m/s is not accelerating, it is not getting any faster or any slower. Therefore the rate of change of its velocity is zero. However, if an object is changing velocity then it is accelerating. Acceleration can be both negative, which is deceleration and positive, which is acceleration.
5. If an object starts from a stationary position and accelerates up to a velocity of 10 m/s in 1 second then the acceleration is 10 meters per second per second or 10 m/s/s.
6. If the object started from a stationary position and accelerates up to a velocity of 10 m/s in 50 seconds then the acceleration is 0.2 meters per second per second or 0.2 m/s/s.
7.Units of acceleration are often shown as m/s/s, m/s² or ms-².

As can be seen from these definitions of displacement, velocity and acceleration, they are all very closely related. In fact, in mathematical terms they are directly related and simple conversions exist. The mathematical relationship involves calculus, specifically integration and differentiation.

The mathematical integral of the velocity curve against time, is the displacement. That means if you plot the velocity curve f(x) against time and measure the area under the curve you have the total displacement s. This relationship is shown in Figure 1.
Figure1.jpg Figure 1.
The mathematical differential of the velocity curve f(x) against time, is the acceleration. That means if you plot the velocity curve against time and measure the slope of the curve a at a given point in time T you would have the acceleration at that time. This relationship is shown in Figure 2.
figure2.jpg
The mathematical differential of the velocity curve against time, is the acceleration. That means if you plot the velocity curve against time and measure the slope of the curve at a given point in time you would have the acceleration at that time.
In simple terms these relationships can be described as functions, a function being a representation of a signal. For example, in Figure 3 below, a simple signal exists.
Figure3.jpg

The (x,y) co-ordinates for this curve are as follows in Table 1.



XY
01
12
23
34
45

Table 1
The pattern is clearly repeating and simple in its nature. To express the contents of Table 1 as a function would be (x, f(x)) rather than (x, y) or more commonly denoted as y = f(x). In this case when x = 1 so then y = x + 1 and so on. Therefore the function y = f(x) is actually y = x + 1,
So f(x) = x + 1
This explains the concept of a curve or signal being expressed as a function rather than sets of co-ordinates. Returning to our velocity curve, if the velocity curve against time was represented as a function, it would be
v = f(t)
Where f is the function at a given time (t) the x-axis value, that produces the y-axis value v.
But as a displacement curve it would be represented as the function,
d(t) = ∫v.dt
Where d(t) is the displacement and dt is the change in displacement with time.
Hence as an acceleration curve it would be represented as the function,
a(t) = dv/dt
Where a(t) is the acceleration and dv is the change in velocity in time.
Returning from core mathematics and using DATS to visualise these conversions, we have a simple worksheet as shown in Figure 4.
figure4.jpg
This worksheet takes a vibration signal and performs integration using three different methods and then integrates again on the resulting signals. Thus from one acceleration signal, it is possible to convert to velocity and then to displacement.

Method 1  Integration only.
Method 2  Application of a high pass filter and then perform the integration.
Method 3  Apply the DATS Omega Arithmetic integration algorithm.

Figure 5 shows the acceleration signal  measured by an accelerometer
figure5.jpg
Figure 6 shows the velocity signal from the “integration only” method.
figure6.jpg
Figure 7 shows the velocity signal from a high pass filter and integration method.
figure7.jpg
Figure 8 shows the velocity signal from the Omega Arithmetic integration method.
figure8.jpg
Figure 9 shows the displacement signal, created by performing the integration on a velocity signal as in Figure 6.
figure9.jpg
Figure 10 shows the displacement signal, created by performing a high pass filter and the integration on a velocity signal as in Figure 7.
figure10.jpg
Figure 11 shows the displacement signal, created by performing the Omega Arithmetic integration on a velocity signal as in Figure 8.
figure11.jpg
These graphs show the different results from our three methods of the conversion between acceleration, velocity and displacement, pay special attention to the y-axis units, these reflect the conversion in question and give some guide to the accuracy of the signals.
It can be seen that, in Figure 6 and Figure 9, the integration only method has produced results which are clearly incorrect. The displacement curve shows a movement of several metres when we know we were measuring displacements of only mm’s. The shape of the curves tells us that there is a factor or constant that is affecting the shape of the curve. The data appears to go in the same direction and is constantly increasing in magnitude. This is because of the low frequency or DC content of the signal. This causes an effect which throws out the conversion process and the integration cannot account for this DC content. This error builds up as the signal is integrated and gives this growing or decreasing error effect. As can be seen from Figure 6 the actual valid part of the signal can just be seen but is very small, it appears to be super imposed on the growing error. It is clear from this that Method 1 is not the correct procedure.
As Figure 7 and Figure 8 show very similar signals, one might expect there to be no difference, but on closer inspection of the y-axis values it is possible to see the filter and integrate method has left a slight DC offset present in the signal. That is, the origin is not about zero when we know that it should be. This same pattern is repeated in Figure 9 and Figure 10. Figures 12 & 13 show the velocity and displacement from Method 2 and Method 3 superimposed.
figure12.jpg
figure13.jpg
This leaves the Omega Arithmetic method for discussion, after experimentation it has been proven to be the only valid method. The reason for this is that, with Omega Arithmetic, the integration is completed in the frequency domain and not in the time domain. The signal is converted to the frequency domain with an FFT, integrated or differentiated then using an inverse FFT converted back to the time domain.

In summary, if converting from Acceleration to Velocity to Displacement, the required conversion is Integration, to go the other way differentiation is used.
Simply applying calculus to a time domain signal is not an acceptable method to perform this conversion.
Filtering in the time domain to remove any DC content, for example filtering out 5 Hz or below, then integrating does produce reasonable looking results, but they are not correct.
The correct conversion method is Omega Arithmetic.
OmegaArithmetic.pdf (102.08 KB, 下载次数: 361)

点评

赞成: 4.0
赞成: 5
  发表于 2013-6-4 07:10
赞成: 3
  发表于 2012-6-7 17:06

评分

1

查看全部评分

发表于 2010-12-27 13:44 | 显示全部楼层
学习了~不知楼主有没有更加具体的实现方法
发表于 2011-1-15 16:25 | 显示全部楼层
希望是不错的东西
下载了学习一下
发表于 2011-1-17 08:53 | 显示全部楼层
不就是AVD技术吗?东方所有
发表于 2011-1-19 15:41 | 显示全部楼层
好东西,感谢楼主,下载来study一下
发表于 2011-1-19 18:06 | 显示全部楼层
发表于 2011-1-20 21:03 | 显示全部楼层
感谢
发表于 2011-1-26 21:34 | 显示全部楼层
是一篇不错的文章,工作中经常用到通过实测加速度来推断伺服位移的问题。是需要好好学习一下了
发表于 2011-2-15 16:41 | 显示全部楼层
正在找这东西呢!
非常感谢!
发表于 2011-2-15 23:31 | 显示全部楼层
这个不错,谢谢分享,说得很详细
发表于 2011-2-19 16:30 | 显示全部楼层
发表于 2011-2-19 16:50 | 显示全部楼层
下载学习一下,谢谢分享。
发表于 2011-2-20 14:48 | 显示全部楼层
不错,好东西,学习了
发表于 2011-2-20 15:45 | 显示全部楼层
好东西,感谢楼主!!!!
您需要登录后才可以回帖 登录 | 我要加入

本版积分规则

QQ|小黑屋|Archiver|手机版|联系我们|声振论坛

GMT+8, 2024-4-20 13:52 , Processed in 0.065764 second(s), 27 queries , Gzip On.

Powered by Discuz! X3.4

Copyright © 2001-2021, Tencent Cloud.

快速回复 返回顶部 返回列表